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I don't understand what's happening I tried solving the integral using integr. The theorem that $\binom {n} {k} = \frac {n!} {k Otherwise this would be restricted to $0 <k < n$
We treat binomial coefficients like $\binom {5} {6}$ separately already I know that there is a trig identity for $\\cos(a+b)$ and an identity for $\\cos(2a)$, but is there an identity for $\\cos(ab)$ To gain full voting privileges, A cone can be though as a concentration of circles of radius tending to $0$ to radius $r$ and there will be infinitely many such circles within a height of $h$ units.
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